- math test (fraction and some of the financial literacy materials) on Friday, April 1
March 29, 2021
Problem solving with fractions
a. 2 5/8 + 1 1/8 = 3 + (5/8 + 1/8)
Answer: 3 6/8, reduce to 3 ¾
b. 4 ¼ + 2 ¾ = 6 4/4 = 6 + 1 = 7Kg
c. 3 2/5 + 1 1/5 = 4 3/5 Km
d. 2/3 + ½ = (2 x 2/3) + (3 x ½)
= 4/6 + 3/6
= 7/6 = 1 1/6
e. 3 3/5 – 1/3
Common denominator between 3 and 5 = 15
Change these fractions with denominator of 15
3 3/5 = 3 (3x3)/(3x5) = 3 9/15
1/3 = (1x5)/(3x5) = 5/15
3 9/15 + 5/15 = 3 4/15Kg
f. 4 2/3 – 1 1/5
Common denominator between 3 and 5 = 15
Change these fractions with denominator of 15
4 2/3 = 4 (5x2)/(5x3) = 4 10/15
1 1/5 = 1 (1 x3)/(3x5) = 1 3/15
4 10/15 – 1 3/15 = 3 7/15 litres left
g. 5 ¼ – 3 7/12
Common denominator between 4 and 12 = 12
Change these fractions with denominator of 12
5 ¼ = 5 (1x3)/(3x4) = 5 3/12
5 3/12 – 3 7/12 = 4 15/12 – 3 7/12 = 1 8/12
(the fraction part, 3/12 – 7/12. I need to borrow from
The whole number so that the first fraction is larger
So that I can subtract
5 3/12 = 4 15/12
(1 whole = 12/12)
5 – 1 = 4 (whole number part)
Add 12/12 to 3/12 = 15/12 (so that I can subtract 7/12
1 8/12 = 1 2/3 Kg left
h. a. 9/10 – 5/6
Common denominator between 10 and 6 = 30
Change these fractions with denominator of 30
9/10 = (9x3)/(3x10) = 27/30
5/6 = (5x5)/(5x6) = 25/30
27/30 – 25/30 = 2/30 left = 1/15 left
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